(4y^2-5y+5)-(3y^2-5y+6)=

Solution for (4y^2-5y+5)-(3y^2-5y+6)= equation:

Simplifying
(4y2 + -5y + 5) + -1(3y2 + -5y + 6) = 0

Reorder the terms:
(5 + -5y + 4y2) + -1(3y2 + -5y + 6) = 0

Remove parenthesis around (5 + -5y + 4y2)
5 + -5y + 4y2 + -1(3y2 + -5y + 6) = 0

Reorder the terms:
5 + -5y + 4y2 + -1(6 + -5y + 3y2) = 0
5 + -5y + 4y2 + (6 * -1 + -5y * -1 + 3y2 * -1) = 0
5 + -5y + 4y2 + (-6 + 5y + -3y2) = 0

Reorder the terms:
5 + -6 + -5y + 5y + 4y2 + -3y2 = 0

Combine like terms: 5 + -6 = -1
-1 + -5y + 5y + 4y2 + -3y2 = 0

Combine like terms: -5y + 5y = 0
-1 + 0 + 4y2 + -3y2 = 0
-1 + 4y2 + -3y2 = 0

Combine like terms: 4y2 + -3y2 = 1y2
-1 + 1y2 = 0

Solving
-1 + 1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 1y2 = 0 + 1
1y2 = 0 + 1

Combine like terms: 0 + 1 = 1
1y2 = 1

Divide each side by '1'.
y2 = 1

Simplifying
y2 = 1

Take the square root of each side:
y = {-1, 1}